A dielectric-filled parallel-plate capacitor has plate area = 15.0 , plate separation = 8.00 and dielectric constant = 2.00. The capacitor is connected to a battery that creates a constant voltage = 7.50 . Throughout the problem, use = 8.85×10−12 .Part AFind the energy of the dielectric-filled capacitor.Express your answer numerically in joules.Part BThe dielectric plate is now slowly pulled out of the capacitor, which remains connected to the battery. Find the energy of the capacitor at the moment when the capacitor is half-filled with the dielectric.Express your answer numerically in joules.Part CThe capacitor is now disconnected from the battery, and the dielectric plate is slowly removed the rest of the way out of the capacitor. Find the new energy of the capacitor, .Express your answer numerically in joules.Part DIn the process of removing the remaining portion of the dielectric from the disconnected capacitor, how much work is done by the external agent acting on the dielectric?Express your answer numerically in joules.
“PLACE THIS PAPER OR A SIMILAR PAPER WITH NURSING ESSAY TUTORS AND GET AN AMAZING DISCOUNT”
The post A dielectric-filled parallel-plate capacitor has plate area = 15.0 , plate separation = 8.00 and dielectric constant = 2. appeared first on Nursing Essay Tutors.
A dielectric-filled parallel-plate capacitor has plate area = 15.0 , plate separation = 8.00 and dielectric constant = 2. was first posted on August 18, 2020 at 1:48 pm.
©2019 “topgradeassignments.org”. Use of this feed is for personal non-commercial use only. If you are not reading this article in your feed reader, then the site is guilty of copyright infringement. Please contact me at administrator@topgradeassignments.org